Therefore, the 10th percentile of the standard normal distribution is -1.28. We look to the leftmost of the row and up to the top of the column to find the corresponding z-value. We search the body of the tables and find that the closest value to 0.1000 is 0.1003. Since the entries in the Standard Normal Cumulative Probability Table represent the probabilities and they are four-decimal-place numbers, we shall write 0.1 as 0.1000 to remind ourselves that it corresponds to the inside entry of the table. The question is asking for a value to the left of which has an area of 0.1 under the standard normal curve. \(P(2 < Z < 3)= P(Z < 3) - P(Z \le 2)= 0.9987 - 0.9772= 0.0215\). Then, we go up and to the left of the probability to find the z-score: Now that we know the z-score, we are going to plug the z-score, mean, and standard deviation into the z-score equation and solve for : (2.93) 9.24 (9.24)(2.93) 9.24 (9. To find the probability between these two values, subtract the probability of less than 2 from the probability of less than 3.
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